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Now instead a 3-mw laser of wavelength λ = 760 nm is directed into the interferometer (with the mirror m1 at the displacement calculated in part a). how much power is detected at d1?

Respuesta :

power received will always remain same and does not depends on the distance

it will be same as the power of source

[tex]P = 3 mW[/tex]

now the energy released by one photon is given as

[tex]E = \frac{hc}{\lambda}[/tex]

[tex]E = \frac{6.6* 10^{-34}* 3 * 10^8}{760 * 10^{-9}}[/tex]

[tex]E = 2.6 * 10^{-19} J[/tex]

now let say N photons per second released

[tex]N * 2.6 * 10^{-19} = 3 * 10^{-3}[/tex]

[tex]N = 1.15* 10^{16} per\: second[/tex]

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