We have the equation of motion
[tex]v^2 = u^2+2as[/tex] , where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
In this case initial velocity = 2.20 m/s, final velocity = 0 m/s, displacement = 14 m
On substitution we will get 0 = [tex]2.20^2+2*a*14[/tex]
On solving we can find the acceleration value as -0.173[tex]m/s^2[/tex]
So free fall acceleration = 0.173[tex]m/s^2[/tex]
