we know the difference of consecutive integers is 1 so we can achieve every next integer by adding 1 in the previous integer .
let us start with assuming the four consecutive integers as :
x , x+1 , x+2 , x+3
3 times ( sum of first two ) = sum of last two + 70
3 ( x+ x+1) = x+2+x+3 + 70
3( 2x +1 ) = 2x + 75
6x + 3 = 2x + 75
6x-2x = 75 - 3
4x = 72
x= 72/4 = 18
so first integer is x= 18 next is 19 next 20 and next 21
Answer : 18 ,19,20,21
