petriajack8008
petriajack8008
08-07-2018
Mathematics
contestada
(−14x^3y^3+4x^5 y6)÷(2x^4y^5)
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claudettoterohil
claudettoterohil
08-07-2018
( - 14x^3)(y^3) + 4x^5y^6)/(2x^4y^5)
= 4x^5y^6 - 14x^3y^3/2x^4y^5
= 4x^2y^3 - 14/2xy^2
= 2x^2y^3 - 7/xy^2
Answer: 2x^2y^3 - 7/xy^2
Hope that helps!!!!
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