Respuesta :
Okay, haven't done physics in years, let's see if I remember this.
So Coulomb's Law states that [tex]F = k \frac{Q_1Q_2}{d^2}[/tex] so if we double the charge on [tex]Q_1[/tex] and double the distance to [tex](2d)[/tex] we plug these into the equation to find
[tex]F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}[/tex]
So we see the new force is exactly 1/2 of the old force so your answer should be [tex]\frac{1}{2}F[/tex] if I can remember my physics correctly.
So Coulomb's Law states that [tex]F = k \frac{Q_1Q_2}{d^2}[/tex] so if we double the charge on [tex]Q_1[/tex] and double the distance to [tex](2d)[/tex] we plug these into the equation to find
[tex]F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}[/tex]
So we see the new force is exactly 1/2 of the old force so your answer should be [tex]\frac{1}{2}F[/tex] if I can remember my physics correctly.
