Respuesta :

gmany
[tex]\text{The domain:}\ x\neq0[/tex]

[tex]\dfrac{1}{x}+\dfrac{1}{3} < \dfrac{1}{5}\ \ \ \ |\cdot15\\\\\dfrac{15}{x}+5 < 3\ \ \ \ |-3\\\\\dfrac{15}{x}+2 < 0\\\\\dfrac{15}{x}+\dfrac{2x}{x} < 0\\\\\dfrac{15+2x}{x} < 0\iff x(15+2x) < 0\\\\x=0;\ x=-\dfrac{15}{2}[/tex]
[tex]\text{Answer:}\ -\dfrac{15}{2} < x < 0[/tex]


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Answer:

A

Step-by-step explanation:

I did the quiz rn

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