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PLEASE ANSWER CORRECTLY ASAP:

Solve this system of equations:

y = x2 – 3x + 12

y = –2x + 14

Substitute the values of x, –1 and 2, into either original equation to solve for the values of y.

What are the solutions of the system of equations?

One solution is (–1, __ )

The second solution (2, ___)

Respuesta :

apologiabiology
first one, subsitute x=-1 for x

[tex]y=(x)^2-3(x)+12[/tex]
[tex]y=(-1)^2-3(-1)+12[/tex]
[tex]y=1+3+12[/tex]
[tex]y=16[/tex]
so one solution is (-1,16)


2nd one, subsitute 2 for x

[tex]y=(x)^2-3(x)+12[/tex]
[tex]y=(2)^2-3(2)+12[/tex]
[tex]y=4-6+12[/tex]
[tex]y=10[/tex]
the second soltuion is (2,10)



so one solution is (-1,16)
the second solution is (2,10)

Answer:

3

Step-by-step explanation:

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