proton (mp=1.67×10−27mp=1.67×10-27 kg, Qp=1.6×10−19Qp=1.6×10-19 C) is accelerated from rest by a 9.5-kV potential difference. Find the linear momentum acquired by the proton.
The linear momentum, P =
Then the proton enters a region with constant 0.75-Tesla magnetic field. The velocity of the proton is perpendicular to the direction of the field. Find the radius of the circle along which the proton moves.
The radius, R =