Describe why L'Hopital's 3x² + 4x + 1 (a) lim x 2 (b) lim (c) lim Rule is used incorrectly for the following limits: 6x + 4 6 = lim lim 3 x+2 2r-1 x-2 2e2z lim 2e = 2 2-0 x 2 x² e2x - I-0 e² = lim гд 0+х - e-z -e = lim 2+[infinity] 1+e-z x-x-e-I lim 1 = 1 [infinity]0+I =